6(y+5)=3[2(y-3)+1]+5

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Solution for 6(y+5)=3[2(y-3)+1]+5 equation: 


Simplifying
6(y + 5) = 3[2(y + -3) + 1] + 5

Reorder the terms:
6(5 + y) = 3[2(y + -3) + 1] + 5
(5 * 6 + y * 6) = 3[2(y + -3) + 1] + 5
(30 + 6y) = 3[2(y + -3) + 1] + 5

Reorder the terms:
30 + 6y = 3[2(-3 + y) + 1] + 5
30 + 6y = 3[(-3 * 2 + y * 2) + 1] + 5
30 + 6y = 3[(-6 + 2y) + 1] + 5

Reorder the terms:
30 + 6y = 3[-6 + 1 + 2y] + 5

Combine like terms: -6 + 1 = -5
30 + 6y = 3[-5 + 2y] + 5
30 + 6y = [-5 * 3 + 2y * 3] + 5
30 + 6y = [-15 + 6y] + 5

Reorder the terms:
30 + 6y = -15 + 5 + 6y

Combine like terms: -15 + 5 = -10
30 + 6y = -10 + 6y

Add '-6y' to each side of the equation.
30 + 6y + -6y = -10 + 6y + -6y

Combine like terms: 6y + -6y = 0
30 + 0 = -10 + 6y + -6y
30 = -10 + 6y + -6y

Combine like terms: 6y + -6y = 0
30 = -10 + 0
30 = -10

Solving
30 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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